How do I derive a type class for different type parameters?
Ben_Yu at asc.aon.com
Ben_Yu at asc.aon.com
Thu Oct 16 14:40:28 EDT 2003
Hi there,
I'm having a problem with type classes.
I have a class called PrettyPrintable,
For data type:
data Generic a = ......
I need to provide instance of Generic a for type class PrettyPrintable.
The parameter type a could be either PrettyPrintable or Show.
If I write the following, it won't compile:
instance Show a => PrettyPrintable (Generic a) where
......
instance PrettyPrintable a => PrettyPrintable (Generic a) where
...
How do I achieve this?
Another alternative that I think may work is if I can say "all Show a will
be PrettyPrintable a in terms of this implementation". But it seems that
the following code won't compile either:
instance Show a => PrettyPrintable a where
......
Am I doing the design totally wrong? Or there is actually some clever
scheme in Haskell that can do this elegantly?
Thanks.
Ben.
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