How to make Parser explicitly "fail"?
L BB
utlbb@yahoo.com
Sat, 1 Mar 2003 23:35:03 -0800 (PST)
Hi, there. I am glad to join Haskell community. :)
Here I have a question about Parser: how to make a
parser explicitly "fail"?
My question arises from the syntax below:
<statement>::=<keyword><seperator><variable>
<keyword>::="define"
<seperator>::=':'
<variable>::=identifier other than <keyword>
<identifier>::=(<letter>)+
<letter>::=a..z|A..Z
Now I am thinking of writing a Parser for variable. My
thought is:
variable::Parser String
variable = do s<-identifier
if not (s=="define") then return s else
--let parser fail
I will be very happy if there is some mechanism to
implement the "else" branch, for I have thought of it
for long. :)
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