two easy questions
Hal Daume III
hdaume@ISI.EDU
Thu, 20 Feb 2003 09:24:38 -0800 (PST)
succ Blue cannot return MrX unless Blue and MrX have the same type. What
I meant was that you would say:
'succ (Detective Red)' ==> Detective Green
'succ (Detective Green)' ==> Detective Blue
'succ (Detective Blue)' ==> Fugitive MrX
--
Hal Daume III
"Computer science is no more about computers | hdaume@isi.edu
than astronomy is about telescopes." -Dijkstra | www.isi.edu/~hdaume
On Thu, 20 Feb 2003, Mike T. Machenry wrote:
> I tried this. It doesn't work. succ Blue is an exception. Anybody else know
> how this should be done?
>
> Thanks,
> -mike
>
> On Thu, Feb 20, 2003 at 08:00:04AM -0800, Hal Daume III wrote:
> > > Question 1: Is there an easier, more elegant way to write this code?
> >
> > For the most part, no.
> >
> > > Question 2: Is there a way to express the following relationship?
> > > I want to have a set of symbols with ordering and another set that is
> > > part of that ordering but with a different parent. For exammple,
> > >
> > > data Player = Detective | Fugitive deriving (Enum)
> > > data Detective = Red | Green | Blue deriving (Enum)
> > > data Fugitive = MrX deriving (Enum)
> >
> > How about something like:
> >
> > > data Player = Detective Detective | Fugitive Fugitive deriving (Enum)
> > > data Detective = Red | Green | Blue deriving (Enum)
> > > data Fugitive = MrX deriving (Enum)
> >
> > (I'm not sure if the deriving Enum on Player will be exactly what you want
> > -- I think so though. I don't derive this class very often.)
> >
> > Then you can test detectiveness by:
> >
> > > isDetective (Detective _) = True
> > > isDetective _ = False
> >
> > HTH
> >
> > - Hal
> >
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