Haskell and algebra

[Frank Atanassow]

Frank Atanassow wrote:

> Gustavo Villavicencio wrote:
> 
>  > Hi all,
>  >
>  > I am trying to understand the algebraic laws and operators
>  > behind a functional expression...
>  >
>  > f >>= g \equiv g* . f
>  >
>  > in the Kleisli Star context. Is this right?
> 
> Yep.

Oops, or rather, not quite.

   m >>= g

means

   g* m

The Kleisli composition (-)* . (-) is sometimes written as (@@):

   (@@) :: (Monad m) => (b -> m c) -> (a -> m b) -> (a -> m c)
   (f @@ g) x = let m = f x in m >>= g

Regards,
Frank