newbie Q: [a] -> [[a]]

[Vardhan Varma]

Hello,
 Please help me with this:
 I'm absolute newbie in Haskell,
 I hope I'm posting to right forum.

(1) For  "abcdefgh" -> ["ab","cd","ef"]
I figured this out:
 foo (x:y:z) = ( (x:y) :(foo z))
Now how generalize this to club 'n' chars instead of two ?
  3 -> "abcdefgh" -> ["abc","def","gh"]
  i.e. n -> [Char] -> [ [Char] ]  -- all except last element 
                                  have length == n

(2) My original problem is of splitting by markers.
    "a<b>cd<efg>hi" -> [ "a" , "b", "cd", "efg", "hi" ]
  I'm at total loss on how to do it.
  Any pointer will be appreciated.

--TIA
--Vardhan