using composition with multiple argument functions

[Ashley Yakeley]

At 2002-02-01 10:45, Dean Herington wrote:

>h1 :: (a -> a -> (a,a)) -> (a -> a -> (a,a)) -> (a -> a -> (a,a))
>h1 = f1 # g1

I think you mean:

h1 :: (a -> a -> (a,a)) -> (a -> a -> (a,a)) -> (a -> a -> (a,a))
h1 f g = f # g


-- 
Ashley Yakeley, Seattle WA