io monad question
Wojciech Moczydlowski, Jr
khaliff@astercity.net
Sun, 13 May 2001 11:07:54 +0200 (CEST)
On Sun, 13 May 2001, luc wrote:
> i designed some basic functions, , mainly String -> [String], or similar with types, plus some more complex datatypes.
>
> Up to now; i was testing them on a basic database I was creating in the core main, "by hand".
> Then i added a basic parser with happy; and bingo; my test database is now loaded from a file... as IO String..; huh!
>
> after a second though; this makes sense, except that i have to change all the type of my functions; now IO String..
>
> plus a few that just dont compile; and i cant understand why...
>
> my question:
> I had to change most of my type of the functions.as is propagated through the code. (i.e. f need g; that need h; etc...) to add IO.
> is that kind of propagation normal, or can i Stop it somewhere ? how?
You can stop it at the very beginning:
f :: String -> String
g :: [A] -> [B] -- etc, any functions without IO
parse :: [String] -> [ A ]
main = do
h <- openFile "sampleFile" ReadMode
contents <- hGetContents h
-- and now you have file contents binded to contents and you can apply your
--functions any way you want, i. e.
let result = g (parse contents)
putStrLn (show result)
Wojciech Moczydlowski, Jr