Implict parameters and monomorphism

John Hughes rjmh@cs.chalmers.se
Thu, 3 May 2001 09:48:20 +0200 (MET DST)


	But a term with an "implicit" argument is a function no matter how you turn
	it, you just don't write the argument explicitely.

I don't buy that. You could equally well say a term with a free variable is
a "function" (of the environment): sure it is, but if it's bound with a let
then the function is called only once.

John