default for quotRem in terms of divMod?
Isaac Dupree
isaacdupree at charter.net
Tue Aug 7 17:08:57 EDT 2007
In class Integral, divMod has a default in terms of quotRem.
(quot,rem,div,mod all have defaults as the both-function they're part
of.) I'm sure divMod is more natural than quotRem to implement for some
types... so why doesn't quotRem have a default in terms of divMod? it
has no default! Then the "minimal to implement" will change from
(toInteger and quotRem) to (toInteger and (quotRem or divMod)).
Isaac
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