public/private module sections

[Lennart Augustsson]

In Cayenne it's:

public
foldr            :: (a -> b -> b) -> b -> [a] -> b
foldr f z []     =  z
foldr f z (x:xs) =  f x (foldr f z xs)

And I quite like it. :)

	-- Lennart

Jared Updike wrote:
> And this
> 
> public foldr            :: (a -> b -> b) -> b -> [a] -> b
> public foldr f z []     =  z
> public foldr f z (x:xs) =  f x (foldr f z xs)
> 
> or is it
> 
> public foldr            :: (a -> b -> b) -> b -> [a] -> b
> foldr f z []     =  z
> foldr f z (x:xs) =  f x (foldr f z xs)
> 
> and now things aren't lined up.
> 
>   Jared.
> 
> On 2/24/06, Bulat Ziganshin <bulat.ziganshin at gmail.com> wrote:
>> Hello Claus,
>>
>> Friday, February 24, 2006, 7:53:09 PM, you wrote:
>>
>> CR> public class C a
>> CR>     where
>> CR>         public m1 :: a
>> CR>         private m2 :: a -> String
>>
>> please don't stop on this!
>>
>> public map (private f) (public (private x:public xs)) =
>>   private (public f (private x))
>>   `public :`
>>   private map (public f) (private xs)
>>
>>
>> --
>> Best regards,
>>  Bulat                            mailto:Bulat.Ziganshin at gmail.com
>>
>> _______________________________________________
>> Haskell-prime mailing list
>> Haskell-prime at haskell.org
>> http://haskell.org/mailman/listinfo/haskell-prime
>>
> 
> 
> --
> http://www.updike.org/~jared/
> reverse ")-:"
> _______________________________________________
> Haskell-prime mailing list
> Haskell-prime at haskell.org
> http://haskell.org/mailman/listinfo/haskell-prime
>