[Haskell-cafe] Does an unboxed unit get pushed to the stack?

[Tom Ellis]

If I define bar and baz as below then, as I understand it, calling baz
requires pushing an argument onto the machine stack.  Is the same true
for baz, or is "calling" baz the same as "calling" foo, i.e. no
argument needs to be pushed?
    
Thanks,

Tom


    {-# LANGUAGE MagicHash #-}
    {-# LANGUAGE UnboxedTuples #-}
    
    module Bar where
    
    import GHC.Prim
    
    foo :: Int
    foo = 1

    bar :: (# #) -> Int
    bar (# #) = 1
    
    baz :: () -> Int
    baz () = 0