[Haskell-cafe] inference with implicitparams seems broken
J. Reinders
jaro.reinders at gmail.com
Wed Mar 23 14:56:09 UTC 2022
It’s due to the monomorphism restriction [1]. If you give `baz` an argument it does infer the type correctly:
```
foo :: Int
foo = bar
where
bar = withX 42 (baz ())
baz () = somethingThanNeedsX
```
Or you can disable the monomorphism restriction:
```
{-# LANGUAGE NoMonomorphismRestriction #-}
```
[1] https://wiki.haskell.org/Monomorphism_restriction
> On 23 Mar 2022, at 15:48, rowan goemans <goemansrowan at gmail.com> wrote:
>
> Hello everyone,
>
> I wonder why the following taken from an stackoverflow answer doesn't work: https://stackoverflow.com/questions/71184922/is-it-possible-to-infer-a-type-that-is-a-reflection-like-closure. Code of the answer posted here verbatim:
>
> ```
> {-# LANGUAGE ImplicitParams #-}
> {-# LANGUAGE RankNTypes #-}
>
> module Temp where
>
> withX :: Int -> ((?x :: Int) => r) -> r
> withX x r =
> let ?x = x
> in r
>
> somethingThanNeedsX :: (?x :: Int) => Int
> somethingThanNeedsX = ?x + 2
>
> foo :: Int
> foo = bar
> where
> bar = withX 42 baz
>
> baz = somethingThanNeedsX
> ```
>
> This won't compile with the error message:
>
> ```
> Orig.hs:19:11: error:
> • Unbound implicit parameter (?x::Int)
> arising from a use of ‘somethingThanNeedsX’
> • In the expression: somethingThanNeedsX
> In an equation for ‘baz’: baz = somethingThanNeedsX
> In an equation for ‘foo’:
> foo
> = bar
> where
> bar = withX 42 baz
> baz = somethingThanNeedsX
> |
> 19 | baz = somethingThanNeedsX
> ```
>
> If you give `baz` a type signature which includes the implicit param it compiles. But I think this is a bug. GHC should not require a type signature here. I tried searching for a GHC ticket but I couldn't find one. But that might also be down to me not using the right query.
>
> Anyway my question is, is this expected behavior? This really makes implicit params less ergonomic.
>
> Best regards,
>
> Rowan Goemans
>
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