[Haskell-cafe] ghci's choice of names for type variables
Richard Eisenberg
lists at richarde.dev
Mon Nov 1 20:48:17 UTC 2021
Joachim is right that, when you use a function that's already defined somewhere, GHC will use its choice of type variable names. That explains all the 'a's you observe. As for the others, `t` is GHC's letter of choice most of the time, and it's hard to predict (even for me, with pretty deep knowledge of the type checker) when it will use `p`.
Bottom line: don't think about this too much -- there's not much of a signal in the noise. :)
Richard
> On Oct 30, 2021, at 7:06 AM, Julian Bradfield <jcb at inf.ed.ac.uk> wrote:
>
> I have tried to answer this by google and the list archives, but
> without success, though it wouldn't surprise me if there is a post
> buried somewhere.
>
> This is GHCI 8.10.7.
>
> When ghci infers types, it sometimes produces types with "a", with
> "t", and with "p" (and maybe others), as in the following set of
> examples:
>
> Prelude> h (x : xs) = x
> Prelude> :t h
> h :: [a] -> a
> Prelude> foo f x = not(f x)
> Prelude> :t foo
> foo :: (t -> Bool) -> t -> Bool
> Prelude> bar f x = (f x) + 1
> Prelude> :t bar
> bar :: Num a => (t -> a) -> t -> a
> Prelude> barb f x g y = (f x)+(g y)
> Prelude> :t barb
> barb :: Num a => (t1 -> a) -> t1 -> (t2 -> a) -> t2 -> a
> Prelude> gar f x = f x
> Prelude> :t gar
> gar :: (t1 -> t2) -> t1 -> t2
> Prelude> fooa x = x
> Prelude> :t fooa
> fooa :: p -> p
>
> What is its rationale? I have attempted to find it in the typechecker
> code, and I see things that suggest "t" is something to do with tau
> types (monotypes?), and "p" has something to do with levels, but going
> from basic Haskell and a modest theoretical acquaintance with System F to
> being able to read the GHCi type-checker is several steps too far!
>
> Can somebody give me a brief explanation of what's going on? In
> particular, is there actual information about the types in the choice
> of letters, or is it just incidental information about the way type
> inference proceeded?
>
> Thanks,
> Julian.
>
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