[Haskell-cafe] Maybe won't let me count
CASANOVA Juan
Juan.Casanova at ed.ac.uk
Mon Mar 29 06:11:36 UTC 2021
As others explained, you still can't do (1 + whereIsBM Ix), you need to unwrap the whereIsBM value or use fmap (<$>).
Here, let me give you a small modification on your code that will do it:
whereIsBM boiList = case boiList of
Nothing -> Nothing
Just (Cons idx lx)
| (idx == Bacon) -> Just 1
| otherwise -> (1 +) <$> (whereIsBM lx)
And as others have explained, what this does is take the result of (whereIsBM Ix), which is a Maybe-wrapped value, and apply the function ((1 +) <$>) (alternatively, (fmap (1 +))), which basically just takes the function (1 +) (add 1 to a number) and applies it to whatever is wrapped inside the Maybe (your numbers), while keeping the Maybe structure. So if the result of (whereIsBM x) is Nothing, then applying ((1 +) <$>) will return Nothing because there's nothing wrapped, whereas if (whereIsBM x) is (Just n), then applying ((1 + ) <$>) to it will return (Just (1 + n)).
You could also, as others explained, case match on the result of (whereIsBM Ix), but that would be more verbose and probably just confuse you. But it is, ultimately, what fmap is actually doing. Unwrapping and re-wrapping.
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Sent: 29 March 2021 05:27
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Subject: Re: [Haskell-cafe] Maybe won't let me count
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I'm not getting past
whereIsBM boiList = case boiList of
Nothing -> Nothing
Just (Cons idx lx)
| (idx == Bacon) -> Just 1
| otherwise -> Just (1 + whereIsBM lx)
...and a few other attempts.
On Sun, Mar 28, 2021 at 10:37 PM Jon Purdy <evincarofautumn at gmail.com<mailto:evincarofautumn at gmail.com>> wrote:
‘whereIsBM’ returns a Maybe-wrapped value, so applying ‘1 + …’ to it would require ‘Maybe a’ to be in ‘Num’, hence the error message. ‘FlexibleContexts’ (ditto ‘FlexibleInstances’) is a pretty benign extension, but it won’t help here, since it just kicks the error down the road a bit.
The basic thing you need to do is match on the Maybe and return ‘Nothing’ if it was ‘Nothing’, or ‘Just (1 + x)’ if it was ‘Just x’ for some x. That can be written quite literally as a ‘case’ expression:
case whereIsBM lx of
Just x -> Just (1 + x)
Nothing -> Nothing
Which could also be written with ‘do’:
do
x <- whereIsBM lx
pure (1 + x)
But this pattern is very common, so it’s already packaged up and generalised as ‘fmap’, a.k.a. ‘<$>’
fmap (1 +) (whereIsBM lx)
-- or
(1 +) <$> whereIsBM lx
On Sun, Mar 28, 2021, 8:13 PM Galaxy Being <borgauf at gmail.com<mailto:borgauf at gmail.com>> wrote:
I've got this
import Data.Maybe
data MyList a = Empty | Cons a (MyList a) deriving (Eq,Ord,Show)
data BaconOrIndex = Bacon | Indx Int deriving (Eq,Ord,Show)
whereIsBM Empty = Nothing
whereIsBM (Cons idx lx) = if (idx == Bacon) then Just 1 else (whereIsBM lx)
which I would like to tell me where the Bacon is (index), not just if there's Bacon, which is what it does now. That is, I need this to happen
> whereIsBM (Cons (Indx 5) (Cons Bacon (Cons (Indx 2) (Cons (Indx 8) Empty))))
Just 2
So I need to traverse a BaconOrIndex list and count how deep I went to find the Bacon variable. I get the above code to evaluate error-free, but obviously I'm only returning a Just 1 when it sees Bacon. What I need is to have the last part be
. . . else (1 + whereIsBM lx)
work; but it keeps giving the error
Non type-variable argument in the constraint: Num (Maybe a)
(Use FlexibleContexts to permit this)
• When checking the inferred type
whereIsBM :: forall a.
(Num a, Num (Maybe a)) =>
MyList BaconOrIndex -> Maybe a
I haven't a clue what this means. Eventually, I'll wrap this in something that handles the Nothing and does fromJust on the alternative. This whole effort is because if I didn't use the Maybe strategy, and said
whereIsBM Empty = 0
...
it would never give back 0 if it didn't find Bacon, rather, it would simply return the whole countdown to Empty. What can I do to make Maybe work here?
LB
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