[Haskell-cafe] Relationship between ((a -> Void) -> Void) and (forall r. (a -> r) -> r)
Li-yao Xia
lysxia at gmail.com
Fri May 15 21:59:22 UTC 2020
Hi Ruben,
> I've seen
> claimed on the web that the CPS transform *is* the double negation [1]
> [2]. I don't think that true, it is almost true in my view. I'll
> explain, these are the types at hand:
>
> type DoubleNeg a = (a -> Void) -> Void
> type CPS a = forall r. (a -> r) -> r
You're reading too much into this claim. When I read "CPS", I would
think of types of the form ((a -> r) -> r), but how the r gets
instantiated or quantified is very context-dependent.
Note that (forall r. (a -> r) -> r) is isomorphic to a. From that, you
can conclude that it is not isomorphic to ((a -> Void) -> Void).
Looking at types only, the correspondence between double negation and
CPS is only a superficial observation that ((a -> Void) -> Void) matches
((a -> r) -> r) simply by setting (r = Void). But CPS is a program
transformation before all. Therefore, to understand the correspondence
with double negation, we should really be looking at the level of terms
(programs or proofs).
1. Define a language of proofs in classical logic. Below is one of many
ways of doing it, notably featuring a rule for double-negation
elimination (NotNot). A term (x :: K a) is a proof of the proposition a.
data K a where
AndI :: K a -> K b -> K (a :*: b)
OrIL :: K a -> K (a :+: b)
OrIR :: K b -> K (a :+: b)
ImplI :: (a -> K b) -> K (a :->: b)
Assumption :: a -> K a
Cut :: K (a :->: b) -> K a -> K b
NotNot :: K (Not (Not a)) -> K a
2. Double negation enables a translation of classical logic in
intuitionistic logic, here embedded in Haskell:
translate :: K a -> Not (Not a)
translate (NotNot p) k =
translate p \f ->
f k
translate (Cut pf px) k =
translate pf \f ->
translate px \x ->
f x k
{- etc. -}
{- also omitted: the translation of formulas ((:*:), (:+:), (:->:), Not)
which is performed implicitly in the above definition of K. -}
Full gist: https://gist.github.com/Lysxia/d90afbe716163b03acf765a2e63062cd
The point is that the proof language K is literally a programming
language (with sums, products, first-order functions, and a weird
operator given by double negation elimination), and the "translate"
function is literally an interpreter in the programming sense, which one
might call a "shallowly embedded compiler", where the target language is
in continuation-passing style.
Thus, CPS transformation and double-negation translation don't just look
similar; when phrased in a certain way, they are literally the same thing.
The translation is not unique. There are multiple flavors of "CPS
transformation" (or "double-negation translation") depending on where
exactly negations are introduced in the translation of formulas.
Cheers,
Li-yao
On 5/15/20 5:19 AM, Ruben Astudillo wrote:
> On 13-05-20 09:15, Olaf Klinke wrote:
>> Excersise: Prove that intuitionistically, it is absurd to deny the law
>> of excluded middle:
>>
>> Not (Not (Either a (Not a)))
>
> It took me a while but it was good effort. I will try to explain how I
> derived it. We need a term for
>
> proof :: Not (Not (Either a (Not a)))
> proof :: (Either a (Not a) -> Void) -> Void
>
> A first approximation is
>
> -- Use the (cont :: Either a (Not a) -> Void) to construct the Void
> -- We need to pass it an Either a (Not a)
> proof :: (Either a (Not a) -> Void) -> Void
> proof cont = cont $ Left <no a to fill in>
>
> Damn, we can't use the `Left` constructor as we are missing an `a` value
> to fill with. Let's try with `Right`
>
> proof :: (Either a (Not a) -> Void) -> Void
> proof cont = cont $ Right (\a -> cont (Left a))
>
> Mind bending. But it does make sense, on the `Right` constructor we
> assume we are have an `a` but we have to return a `Void`. Luckily we can
> construct a `Void` retaking the path we were gonna follow before filling
> with a `Left a`.
>
> Along the way I had other questions related to the original mail and
> given you seem knowledgeable I want to corroborate with you. I've seen
> claimed on the web that the CPS transform *is* the double negation [1]
> [2]. I don't think that true, it is almost true in my view. I'll
> explain, these are the types at hand:
>
> type DoubleNeg a = (a -> Void) -> Void
> type CPS a = forall r. (a -> r) -> r
>
> We want to see there is an equivalence/isomorphism between the two
> types. One implication is trivial
>
> proof_CPS_DoubleNeg :: forall a. CPS a -> DoubleNeg a
> proof_CPS_DoubleNeg cont = cont
>
> We only specialized `r ~ Void`, which mean we can transform a `CPS a`
> into a `DoubleNeg a`. So far so good, we are missing the other
> implication
>
> -- bind type variables: a, r
> -- cont :: (a -> Void) -> Void
> -- absurd :: forall b. Void -> b
> -- cc :: a -> r
> proof_DoubleNeg_CPS :: forall a. DoubleNeg a -> CPS a
> proof_DoubleNeg_CPS cont = \cc -> absurd $ cont (_missing . cc)
>
> Trouble, we can't fill `_missing :: r -> Void` as such function only
> exists when `r ~ Void` as it must be the empty function. This is why I
> don't think `CPS a` is the double negation.
>
> But I can see how people can get confused. Given a value `x :: a` we can
> embed it onto `CPS a` via `return x`. As we saw before we can pass from
> `CPS a` to `DoubleNeg a`. So we have *two* ways for passing from `a` to
> `DoubleNeg a`, the first one is directly as in the previous mail. The
> second one is using `proof_CPS_DoubleNeg`
>
> embed_onto_DoubleNeg :: a -> DoubleNeg
> embed_onto_DoubleNeg = proof_CPS_DoubleNeg . return
> where
> return :: a -> CPS a
> return a = ($ a)
>
> So CPS is /almost/ the double negation. It is still interesting because
> it's enough to embed a classical fragment of logic onto the constructive
> fragment (LEM, pierce etc). But calling it a double negation really
> tripped me off.
>
> Am I correct? Or is there other reason why CPS is called the double
> negation transformation?
>
> Thank for your time reading this, I know it was long.
>
> [1]: http://jelv.is/talks/curry-howard.html#slide30
> [2]:
> https://www.quora.com/What-is-continuation-passing-style-in-functional-programming
>
>
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