[Haskell-cafe] How to fix ambiguous type variable?
marian.jancar at gmx.com
Thu Jun 13 07:50:01 UTC 2019
On 6/13/19 6:36 AM, Boris wrote:
> someCheck :: (Show a, Read a, Eq a) => String -> a -> Bool
> someCheck s v = (read . show . read $ s) == v
someCheck :: (Show a, Read a, Eq a) => String -> a -> Bool
someCheck s v = (r . show . r $ s) == v where r = read
I believe you do intend to use the same read in both cases anyway,
and letting a different read to slip in would be a bug.
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