[Haskell-cafe] mfix for a nested monad
Benjamin Redelings
benjamin.redelings at gmail.com
Thu Oct 25 14:43:08 UTC 2018
Hi,
I'm trying to implement mfix for a monad that is nested inside another
monad. I came up with the following logic for how to implement this,
but I suspect there are some things I'm missing. My conclusion is that I
want
interpret (MFix f) = mfix (interpret.f)
Does this seem right? Has this situation been discussed somewhere?
-BenRI
P.S. Here's what I mean by the monad being nested in another monad.
Let's say that the monad M2 has interpreter i2, with type
i2 :: M2 a -> M1 a
and then M1 is the other monad, and has interpreter i1:
i1 :: M1a -> a
I suppose that the nesting is really a nesting of interpreters.
P.P.S. I came up with some equational reasoning for how to treat mfix in
the i2 interpreter.
(a) For some interpreters `i`, it makes sense to require
i (mfix f) = let x = (i . f) x in x
(b) I want the composition of interpreters (i1.i2) to act like (a) above:
(i1 . i2) (mfix f) = let x = (i1 . i2 . f) x in x
(c) Rearranging, and then substituting using (a):
i1 (i2 (mfix f)) = let x = i1 . (i2 . f) x in x
= i1 (mfix (i2 . f))
(d) Therefore, we could set
i2 (mfix f) = mfix (i2 . f)
I'm probably going to make a `data` declaration for M2 so I could
actually write
i2 (Mfix f) = mfix (i2 . f)
-BenRI
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