[Haskell-cafe] How to unify these three types with identical structures into one definition?
MigMit
migmit at gmail.com
Fri Dec 14 13:17:48 UTC 2018
You probably mean
newtype Expr = Expr (ExprG Expr)
Az iPademről küldve
2018. dec. 14. dátummal, 14:08 időpontban Tobias Brandt <to_br at uni-bremen.de> írta:
> Hello,
>
> my adhoc solution would be to add a type parameter:
>
> data ExprG a = Var String
> | Enclosed String a String
> | Prefix a a
> | Ternary a String a String a deriving Show
>
>
> type Expr = ExprG (ExprG ())
>
> type ExprL = ExprG [Expr]
>
>
> Cheers,
>
> Tobias
>
>
>
>> On 12/14/18 1:56 PM, ducis wrote:
>> Hello,
>>
>> Say I have a certain type for parse trees:
>> data Expr = Var String
>> | Enclosed String Expr String
>> | Prefix Expr Expr
>> | Ternary Expr String Expr String Expr
>> deriving (Show,Eq,Ord,Generic)--,Typeable)
>>
>> Then I want a new type where every occurence of "Expr" definition changed to "[Expr]":
>> data ExprL = VarL String
>> | EnclosedL String [Expr] String
>> | PrefixL [Expr] [Expr]
>> | TernaryL [Expr] String [Expr] String [Expr]
>> deriving (Show,Eq,Ord,Generic)
>>
>> Sometimes, I also want to use a DList instead of list.
>> data ExprD = VarD String
>> | EnclosedD String (DList Expr) String
>> | PrefixD (DList Expr) (DList Expr)
>> | TernaryD (DList Expr) String (DList Expr) String (DList Expr)
>> deriving (Show,Eq,Ord,Generic)
>>
>> They have exactly the same structure, is there a way to unify the three definitions into one?
>> Furthurmore, is it possible to generalise the latter two for all Functors ?
>>
>> Thanks,
>> ducis
>>
>>
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