[Haskell-cafe] fmap use
Damien Mattei
mattei at oca.eu
Fri Dec 14 10:49:45 UTC 2018
hello again,
another question with Haskell, again with my database but that is again
related to Monads:
i have this code in main:
rows <- query_ conn "SELECT Nom,distance FROM AngularDistance WHERE
distance > 0.000278"
let lg = Prelude.length rows
let tst = if lg > 1 then "some" else "one or zero"
it compiles and i assume it works,
and i have a new (for those that have follow my previous posts) function
like this one:
-- this function will return the list of N°BD from WDS for a given name
-- note: there could be multiple result for a given name in WDS due to
components
getBD_WDS :: Connection -> String -> IO Float
getBD_WDS conn name = trace "Entering getBD_WDS" noBDfp
where qry_head = "select DNUM from WDS where DISC = ?" :: Query
bd_rows :: IO [Only Text]
bd_rows = query conn qry_head (Only (name::String))
lg = fmap Prelude.length bd_rows
-- tst = if (fmap lg) > 1 then "some" else "one or zero"
noBDtxt :: IO Text
-- noBDtxt = trace "lg " (fmap (fromOnly . Prelude.head) bd_rows)
noBDtxt = (fmap (fromOnly . Prelude.head) bd_rows)
-- noBDstr :: String
-- noBDstr = Text.unpack noBDtxt
noBDstr :: IO String
noBDstr = fmap Text.unpack noBDtxt
-- noBDfp = read $ noBDstr :: Float
noBDfp :: IO Float
noBDfp = trace "Exiting getBD" (fmap read noBDstr)
the problem is that
first i noticed that in a function to make working the same code than
in Main i had to had almost always fmap before the line,
i admit ,even if i'm teacher in functional programming in Scheme at
University,
i begin in Haskell and i don't always understand what i'm using,
i try to learn it by instinct even if sometimes i read pages about
Functor and Monads i have no time to get in the Mathematics theoretical
knowledge behind Haskell, i try to learn by getting some solutions in
Haskell-cafe and it works, i know now a lot more about Haskell than 2
weeks ago,so....
if someon could explain me a few more about fmap or just give what i
must place in my function instead of
let lg = Prelude.length rows
let tst = if lg > 1 then "some" else "one or zero"
i replace this in the function by:
lg = fmap Prelude.length bd_rows
OK for compilation, but then
tst = if lg > 1 then "some" else "one or zero"
does not compile:
*Main> :load UpdateSidonie
[1 of 1] Compiling Main ( UpdateSidonie.hs, interpreted )
UpdateSidonie.hs:80:18: error:
• No instance for (Ord (IO Int)) arising from a use of ‘>’
• In the expression: lg > 1
In the expression: if lg > 1 then "some" else "one or zero"
In an equation for ‘tst’:
tst = if lg > 1 then "some" else "one or zero"
|
80 | tst = if lg > 1 then "some" else "one or zero"
| ^^^^^^
UpdateSidonie.hs:80:23: error:
• No instance for (Num (IO Int)) arising from the literal ‘1’
• In the second argument of ‘(>)’, namely ‘1’
In the expression: lg > 1
In the expression: if lg > 1 then "some" else "one or zero"
|
80 | tst = if lg > 1 then "some" else "one or zero"
| ^
Failed, no modules loaded.
and even the "fmap miraculous function" as i call it no more works:
tst = if (fmap lg) > 1 then "some" else "one or zero"
Prelude> :load UpdateSidonie
[1 of 1] Compiling Main ( UpdateSidonie.hs, interpreted )
UpdateSidonie.hs:80:24: error:
• Couldn't match expected type ‘a0 -> b0’ with actual type ‘IO Int’
• In the first argument of ‘fmap’, namely ‘lg’
In the first argument of ‘(>)’, namely ‘(fmap lg)’
In the expression: (fmap lg) > 1
|
80 | tst = if (fmap lg) > 1 then "some" else "one or zero"
| ^^
Failed, no modules loaded.
a solution to this proble i think , will help me a lot,
i sticked with problems in haskell i would have already solved in Scheme
or Python, that's really discouraging me of using Haskell, i'm
obstinating myself because i really think it's a great language that
push the programming to high levels of abstractions but for now it's a
bit a nightmare, i must admit it...
--
Damien.Mattei at unice.fr, Damien.Mattei at oca.eu, UNS / OCA / CNRS
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