[Haskell-cafe] Functor instance for FunPB
monkleyon at gmail.com
Sat May 6 19:04:40 UTC 2017
On 2017-05-06 20:38, David Kraeutmann wrote:
> The only lawful instance I can think of is:
> instance Functor (FunPB a) where
> fmap f (FunPB g) = FunPB $ \k -> let (a,b) = g k in (a, fmap f b)
> which is fairly straightforward IMO.
And because it's closer to the original style:
fmap f = FunPB .((.)((<$>).(<$>)$f)). runFunPB
Now it's STARRING INTO YOU SOUL. And it's also so much easier to read.
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