[Haskell-cafe] Using Haskell types in a database
Adam Bergmark
adam at bergmark.nl
Tue Feb 10 18:53:36 UTC 2015
You shouldn't be using derivePersistField here if you want another db type.
As you say there is a predefined mapping but you can override this by
defining custom instances for your newtype.
On Tue, Feb 10, 2015 at 7:11 PM, Bob Ippolito <bob at redivi.com> wrote:
> If you're using Postgres you can use types in the database
> http://www.postgresql.org/docs/9.2/static/sql-createtype.html
>
> I don't know what these look like from the Haskell drivers but you can
> have typed SQL if you want it.
>
>
> On Tuesday, February 10, 2015, Nikita Karetnikov <nikita at karetnikov.org>
> wrote:
>
>> > That part I don't understand. Why does your proposal require varchars
>> > everywhere?
>>
>> That's what Persistent generates (using derivePersistField) for the
>> second table. For example, the Haskell value
>>
>> MyText "foo"
>>
>> where MyText is
>>
>> newtype MyText = MyText Text deriving (Show, Read)
>> derivePersistField "MyText"
>>
>> will be stored in PostgreSQL as a varchar
>>
>> 'MyText "foo"'
>>
>> I assume that Persistent (or its PostgreSQL backend) has a predefined
>> mapping from a commonly used Haskell types to the database types.
>> And everything else is represented as a varchar.
>>
>> So there are two choices, corresponding to the two tables shown in the
>> original message:
>>
>> 1. Design tables with the (basic) database types in mind (integer,
>> boolean, timestamp, varchar, etc.) then wrap and unwrap values each
>> time you interact with the database.
>>
>> 2. Use Haskell types like MyText or something more complex directly
>> and end up with varchar everywhere.
>>
>> I wonder how bad is the second option in practice because
>> wrapping/unwrapping is error-prone. Of course, the varchar thing makes
>> the alarm bells ring in my head, but when does it significantly affect
>> performance? For example, maybe it's okay for a small shop, or is it a
>> no go for everyone?
>>
>
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