[Haskell-cafe] Applicative banana brackets

[Kim-Ee Yeoh]

On Mon, Dec 14, 2015 at 9:38 PM, martin <monkleyon at googlemail.com> wrote:

2) Every arrow a b c is an applicative (a b) c, because comma = (&&&).
> Conversely, every applicative that is polymorphic over some "internal"
> variable is automatically an arrow, through (&&&) = comma.
>

Where is the proof that (a b) is a Functor?

Recall that the class method arr -- the closest kin to fmap -- has the type:

(b -> c) -> a b c.

-- Kim-Ee
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