[Haskell-cafe] groupBy without Ord?

[Kim-Ee Yeoh]

On Sun, Mar 30, 2014 at 9:06 PM, martin <martin.drautzburg at web.de> wrote:

> groupEq (x:xs) = (groupEq a) ++ [x] ++ (groupEq b)
>         where
>             a = filter (==x) xs
>             b = filter (/= x) xs
>

Why the need to recurse on "a"? It's a list of identical elements!



-- Kim-Ee
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