[Haskell-cafe] Could someone help me to understand funB?
Magicloud Magiclouds
magicloud.magiclouds at gmail.com
Fri Dec 19 04:35:48 UTC 2014
Thank you. This will take some time for me to read.
On Fri, Dec 19, 2014 at 12:32 PM, Lyndon Maydwell <maydwell at gmail.com>
wrote:
>
> funB = flip takeWhile primes . ( . join (*)) . flip (<=)
>
> funB x = flip takeWhile primes ((( . join (*)) . flip (<=)) x)
>
> funB x = takeWhile ((( . join (*)) . flip (<=)) x) primes
>
> funB x = takeWhile (foo x) primes
>
>
> foo x = (( . join (*)) . flip (<=)) x
>
> foo x = (( . join (*)) (flip (<=) x)
>
> foo x = flip (<=) x . join (*)
>
> foo x = (x <=) . join (*)
>
>
> -- join :: Monad m => m (m a) -> m a
> -- join (*) == (**2)
>
> foo x = (x <=) . (** 2)
>
> foo x y = x <= (y ** 2)
>
> isLessThanTheSquareOf = foo
>
> funB x = takeWhile (x `isLessThanTheSquareOf`) primes
>
>
> Helpful?
>
>
> On Fri, Dec 19, 2014 at 2:52 PM, Magicloud Magiclouds <
> magicloud.magiclouds at gmail.com> wrote:
>
>> Hi,
>>
>> Following code is to get a list of primes. Now it is hard for me to
>> understand funB. I mean I can see what it does. But I cannot see the
>> detailed process by every language part.
>>
>> import Control.Monad
>>
>> isPrime :: Integer -> Bool
>> isPrime i = ap funA funB i
>>
>> funA :: Integer -> [Integer] -> Bool
>> funA x xs = all (\x' -> (mod x x') /= 0) xs
>>
>> funB :: Integer -> [Integer]
>> funB = flip takeWhile primes . ( . join (*)) . flip (<=)
>>
>> primes :: [Integer]
>> primes = 2 : filter isPrime [3, 5 ..]
>>
>> main :: IO ()
>> main = print $ take 10 primes
>>
>> --
>> 竹密岂妨流水过
>> 山高哪阻野云飞
>>
>> And for G+, please use magiclouds#gmail.com.
>>
>> _______________________________________________
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>>
>>
--
竹密岂妨流水过
山高哪阻野云飞
And for G+, please use magiclouds#gmail.com.
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