[Haskell-cafe] Proposal: New syntax for Haskell
Alberto G. Corona
agocorona at gmail.com
Tue Sep 10 13:43:16 CEST 2013
That was done around 100 years ago with COBOL.
2013/9/10 Vo Minh Thu <noteed at gmail.com>
> The syntax is actually used by non-technical people to write tests.
> Using it to write Haskell code is a joke. (Using it for business
> specification is not, even if for technical people this seems
> overkill.)
>
> Thu
>
> 2013/9/10 Ian Ross <ian at skybluetrades.net>:
> > Me too, but I wasn't brave enough to say so after people seemed to be
> taking
> > it seriously...
> >
> >
> > On 10 September 2013 13:33, Roman Cheplyaka <roma at ro-che.info> wrote:
> >>
> >> * John Wiegley <johnw at fpcomplete.com> [2013-09-10 04:48:36-0500]
> >> > >>>>> Niklas Hambüchen <mail at nh2.me> writes:
> >> >
> >> > > Code written in cucumber syntax is concise and easy to read
> >> >
> >> > concise |kənˈsīs|, adj.
> >> >
> >> > giving a lot of information clearly and in a few words; brief but
> >> > comprehensive.
> >> >
> >> > Compare:
> >> >
> >> > Scenario: Defining the function foldl
> >> > Given I want do define foldl
> >> > Which has the type (in brackets) a to b to a (end of brackets),
> >> > to a, to list of b, to a
> >> > And my arguments are called f, acc, and l
> >> > When l is empty
> >> > Then the result better be acc
> >> > Otherwise l is x cons xs
> >> > Then the result should be foldl f (in brackets) f acc x
> >> > (end of brackets) xs
> >> >
> >> > To:
> >> >
> >> > foldl :: (a -> b -> a) -> a -> [b] -> a
> >> > foldl f z [] = z
> >> > foldl f z (x:xs) = foldl f (f z x) xs
> >> >
> >> > How is that more concise or preferable?
> >>
> >> I thought it was a joke.
> >>
> >> Roman
> >>
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> >>
> >
> >
> >
> > --
> > Ian Ross Tel: +43(0)6804451378 ian at skybluetrades.net
> > www.skybluetrades.net
> >
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> >
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--
Alberto.
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