[Haskell-cafe] type constructor section for (-> Bool), _not_ ((->) Bool)
AntC
anthony_clayden at clear.net.nz
Thu Sep 5 00:23:16 CEST 2013
> Brent Yorgey <byorgey <at> seas.upenn.edu> writes:
>
> > On Tue, Sep 03, 2013 at 11:33:46AM +0000, AntC wrote:
> >
> > I want an instance and type improvement constraint of the form
> >
> > instance (f ~ (-> Bool)) => C Foo (f b) where ...
> >
>
> There is no operator section syntax for types. Moreover, this is not
> just an issue of syntax: it is impossible to partially apply a type
> constructor to anything other than its first argument, because there
> is no type-level lambda.
>
Thank you Brent, so I'm not being entirely dumb ;-).
> >
> > data FlipFun b -- abstract
> > instance (f ~ FlipFun) => C Foo (f b) where ...
> >
> > And a type function inside the class to generate the type.
> > But then I'd have to apply the type function for all instances,
> > and in most places it'd be id.
>
> That's the only way to do it that I know of.
>
OK, I've got that working. My class is a helper doing type discrimination.
So the constraints have 'infected' the caller and the caller's caller,
etc ...
Elegant it ain't.
AntC
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