wren ng thornton
wren at freegeek.org
Tue Jul 23 01:04:33 CEST 2013
On 7/22/13 9:06 AM, Tom Ellis wrote:
> On Mon, Jul 22, 2013 at 07:52:06PM +1200, Chris Wong wrote:
>> A binding is memoized if, ignoring everything after the equals sign,
>> it looks like a constant.
>> In other words, these are memoized:
>> f = \x -> x + 1
>> and these are not:
>> f x = x + 1
> In what sense is the former memoised? I'm not aware of any difference
> between these two definitions.
f1 = let y = blah blah in \x -> x + y
f2 x = let y = blah blah in x + y
The former will memoize y and share it across all invocations of f1;
whereas f2 will recompute y for each invocation.
In principle, we could translate between these two forms (the f2 ==> f1
direction requires detecting that y does not depend on x). However, in
practice, the compiler has no way to decide which one is better since it
involves a space/time tradeoff which: (a) requires the language to keep
track of space and time costs, (b) would require whole-program analysis to
determine the total space/time costs, and (c) requires the user's
objective function to know how to weight the tradeoff ratio.
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