[Haskell-cafe] Comparing functions
allbery.b at gmail.com
Thu Jul 11 20:45:42 CEST 2013
On Thu, Jul 11, 2013 at 2:11 PM, Vlatko Basic <vlatko.basic at gmail.com>wrote:
> The problem here isn't quite what you think it is; (==) is not a
> constructor, therefore it is a *variable*. It's exactly the same problem as
> a = 5
> -- ...
> foo a = 3 -- this does NOT compare with the previous value of "a";
> it's identical to the next line!
> foo x = x
> Hm, I thought it is a pattern match with constant, as in f ('a':xs) ==
I wonder what you'd make of this definition, then?
(*) `on` f = \x y -> f x * f y
brandon s allbery kf8nh sine nomine associates
allbery.b at gmail.com ballbery at sinenomine.net
unix, openafs, kerberos, infrastructure, xmonad http://sinenomine.net
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