[Haskell-cafe] How does one create an input handle bound to a string instead of a file?

Gregory Collins greg at gregorycollins.net
Thu Feb 28 00:23:52 CET 2013


Hm, perhaps I stand corrected. Then how exactly do you make the bytestring
Handle?


On Thu, Feb 28, 2013 at 12:15 AM, Don Stewart <dons00 at gmail.com> wrote:

> I don't think that's right - Simon's buffer class rewrite should have made
> this possible, I think.
>
>
> http://hackage.haskell.org/packages/archive/base/4.2.0.1/doc/html/GHC-IO-BufferedIO.html
> On Feb 27, 2013 10:52 PM, "Gregory Collins" <greg at gregorycollins.net>
> wrote:
>
>> On Wed, Feb 27, 2013 at 9:38 PM, John D. Ramsdell <ramsdell0 at gmail.com>wrote:
>>
>>> How does one create a value of type System.IO.Handle for reading that
>>> takes its input from a string instead of a file?  I'm looking for the
>>> equivalent of java.io.StringReader in Java.  Thanks in advance.
>>>
>>
>> You can't. There are several libraries that purport to provide better
>> interfaces for doing IO in Haskell, like conduit, pipes, enumerator, and my
>> own io-streams library (http://github.com/snapframework/io-streams, soon
>> to be released). You could try one of those.
>>
>> G
>> --
>> Gregory Collins <greg at gregorycollins.net>
>>
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>>


-- 
Gregory Collins <greg at gregorycollins.net>
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