[Haskell-cafe] Is there an escape from MonadState+MonadIO+MonadError monad stack?
roma at ro-che.info
Sat Apr 6 23:42:24 CEST 2013
You forgot to mention what your problem is. :)
What you describe sounds reasonable. Why do you want to "escape"?
* Ömer Sinan Ağacan <omeragacan at gmail.com> [2013-04-07 00:22:58+0300]
> I'm a hobbyist Haskell programmer and my use of Haskell is mostly
> consists of writing interpreters, simple virtual machines, and type
> One thing I'm not happy about my Haskell programs is, almost all of my
> programs have a monad transformer stack consisting MonadError, MonadIO
> and MonadState.
> Let's say I'm writing an interpreter, I certainly need MonadIO to
> interpret object language's IO functions: printing, reading from file
> etc. I also need MonadState for, well, states(dynamic environment
> etc.). MonadError is also required because most computations can
> fail(unbound variable error, type mismatch etc. it can be also used
> for implementing exceptions in object language)
> Same applies for my other applications as well. Type checkers require
> MonadError(unification error etc.), MonadState(to keep substitutions).
> MonadIO is not required in this case. But it also required for virtual
> machines(IOVector for memory -- ST vectors also work, but IO is still
> required for other stuff - printing, display etc.)
> I know these are mostly related with my application area, but I still
> wanted to write this because I may be missing something, or simply
> doing things wrong.
> Advices from experienced Haskell programmers would be appreciated,
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> Haskell-Cafe at haskell.org
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