[Haskell-cafe] foldr (.) id

[Thiago Negri]

Can you please show some examples where it might be useful?
I miss the point.

Thanks,
Thiago.

2012/10/26 John Wiegley <johnw at newartisans.com>:
>>>>>> Greg Fitzgerald <garious at gmail.com> writes:
>
>> I've recently found myself using the expression: "foldr (.) id" to compose a
>> list (or Foldable) of functions.
>
> You want the Endo monoid:
>
>     ghci> appEndo (Endo (+ 10) <> Endo (+ 20)) $ 3
>       33
>
> John
>
>
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