[Haskell-cafe] Does this have a name?

Jacques Carette carette at mcmaster.ca
Mon Nov 5 19:48:11 CET 2012

The function
 > app1 f x = f >>= ($ x)
or equivalently
 > app2 f x = join (f <*> pure x)

with type  Monad m => m (a -> m b) -> a -> m b ?
Hoogle did not help.


PS: a nice point-free version would be appreciated as well.  I can 
easily change app1 and app2 myself to point-free with enough 
applications of flip, . and $, but none of those are 'nice'.

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