[Haskell-cafe] HXT: Replace an element with its text
Michael Orlitzky
michael at orlitzky.com
Tue Jun 26 07:58:20 CEST 2012
I would like to replace,
<body><a href="#">foo</a></body>
with,
<body>foo</body>
using HXT. So far, the closest I've come is to parse the HTML and apply
the following stuff:
is_link :: (ArrowXml a) => a XmlTree XmlTree
is_link =
hasName "a"
replace_links_with_their_text :: (ArrowXml a) => a XmlTree XmlTree
replace_links_with_their_text =
processTopDown $ (getText >>> mkText) `when` is_link
Unfortunately, this just removes the "a" element and its text entirely.
The other-closest solution is,
replace_links_with_their_text :: (ArrowXml a) => a XmlTree XmlTree
replace_links_with_their_text =
processTopDown $ (txt "foo") `when` is_link
Of course, I don't want to hard-code the value "foo", and I can't figure
out a way to feed the element's text back into 'txt'.
Anyone tried this before?
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