[Haskell-cafe] Rewrite this imperative in FP way

[Morel Pisum]

"+= a[i]" is the same as "+=1", isn't it?

(i accidentally didn't reply to the list on my first try. sorry.)


Am 05.02.2012 16:36, schrieb Haisheng Wu:
> Sorry there is a mistake in the problem description.
> Here it is in Python:
>
> a = [1,1,1,1] b = [0,1,2,3] c = [0,2] d = [0,0,0,0]
> for i in b:
>      for j in c:
>          if (i+j)<3:
>                  d[i+j] += a[i]
>
>
> -Haisheng
>
>
> On Sun, Feb 5, 2012 at 2:28 PM, Haisheng Wu<freizl at gmail.com>  wrote:
>
>> a = [1,1,1,1]
>> b = [0,1,2,3]
>> d = [0,0,0,0]
>>
>> for i in b:
>>    for j in c:
>>      if (i+j)<3:
>>        d[i+j] += a[i]
>>
>> My just work implementation in Haskell
>> http://hpaste.org/57452
>>
>> Another people implementation in Haskell with Monad and it turns out
>> complex and very imperatively.
>> http://hpaste.org/57358
>>
>> Do you have any cool solution in FP way?
>>
>> Thanks.
>> -Simon
>>
>
>
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