[Haskell-cafe] Data.Vector.Unboxed

Tom Nielsen tanielsen at gmail.com
Wed Nov 9 12:43:48 CET 2011


I don't know about Unboxed, but you can define a newtype wrapper
around Data.Vector.Storable that includes the size as a type-level


data Z
data S n

newtype Vec n a = Vec (Vector a)

Then you can define a storable instance for Storable a => Vec n a, and
thus you can define a storable vector for Vec n a.

Not that you need something like this because storable instances must
have fixed size. I don't know if this is also true for Unbox.

I've done this using lists as the underlying container inside the
typed vectors, but you could use Data.Vector.Storable instead with
minimal effort:



On Wed, Nov 9, 2011 at 9:56 AM, kaffeepause73 <kaffeepause73 at yahoo.de> wrote:
> Hello,
> quick question about unboxed Vectors :
> Is it possible to create an unboxed vector of unboxed vector ? :
>> import qualified Data.Vector.Unboxed as V
>> type UnboxedNestedVextor =  V.Vector (V.Vector Int)
> Alternatively I would have to use:
>> import qualified Data.Vector.Unboxed as V
>> import qualified Data.Vector as VB
> type UnboxedNestedVextor =  VB.Vector (V.Vector Int)
> Is there a rule of thumb how much quicker Unboxed Vectors are ?
> Cheers Phil
> --
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