[Haskell-cafe] Data.Vector.Unboxed

[Tom Nielsen]

Hi,

I don't know about Unboxed, but you can define a newtype wrapper
around Data.Vector.Storable that includes the size as a type-level
natural.

i.e.

data Z
data S n

newtype Vec n a = Vec (Vector a)

Then you can define a storable instance for Storable a => Vec n a, and
thus you can define a storable vector for Vec n a.

Not that you need something like this because storable instances must
have fixed size. I don't know if this is also true for Unbox.

I've done this using lists as the underlying container inside the
typed vectors, but you could use Data.Vector.Storable instead with
minimal effort:

https://github.com/glutamate/space/blob/master/VectorsL.hs

Tom



On Wed, Nov 9, 2011 at 9:56 AM, kaffeepause73 <kaffeepause73 at yahoo.de> wrote:
> Hello,
>
> quick question about unboxed Vectors :
>
> Is it possible to create an unboxed vector of unboxed vector ? :
>
>> import qualified Data.Vector.Unboxed as V
>> type UnboxedNestedVextor =  V.Vector (V.Vector Int)
>
> Alternatively I would have to use:
>
>> import qualified Data.Vector.Unboxed as V
>> import qualified Data.Vector as VB
>
> type UnboxedNestedVextor =  VB.Vector (V.Vector Int)
>
> Is there a rule of thumb how much quicker Unboxed Vectors are ?
>
> Cheers Phil
>
>
> --
> View this message in context: http://haskell.1045720.n5.nabble.com/Data-Vector-Unboxed-tp4977289p4977289.html
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