[Haskell-cafe] Function application layout

[Jonas Almström Duregård]

That's a useful operator! Unfortunately it does not play nice with $. Of
less importance: some syntactic constructs can not appear in the arguments
without parenthesis, let bindings for instance (although lambda abstraction
works parenthesis-free).

Also I'm not sure this can be used for defining trees or nested function
application since a nesting of the operator inevitably require parenthesis.

/J

On 26 May 2011 14:52, Daniel Fischer <daniel.is.fischer at googlemail.com>wrote:

> On Thursday 26 May 2011 14:35:41, Neil Brown wrote:
> > foo is the function we want to apply, and eg shows how to apply it in
> > do-notation with an argument on each line.  I couldn't manage to remove
> > the r$ at the beginning of each line, which rather ruins the whole
> > scheme :-(  On the plus side, there's no brackets, it's only two extra
> > characters per line, and you can have whatever you like after the r$.
>
> Wouldn't that be also achievable with
>
> infixl 0 ?
>
> (?) :: (a -> b) -> a -> b
> f ? x = f x
>
> eg = foo
>  ? 2 + 1
>  ? 'c'
>  ? "hello" ++ "goodbye"
>  ? 3.0
>
> ?
>
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