[Haskell-cafe] Function application layout
Jonas Almström Duregård
jonas.duregard at chalmers.se
Thu May 26 17:22:10 CEST 2011
That's a useful operator! Unfortunately it does not play nice with $. Of
less importance: some syntactic constructs can not appear in the arguments
without parenthesis, let bindings for instance (although lambda abstraction
Also I'm not sure this can be used for defining trees or nested function
application since a nesting of the operator inevitably require parenthesis.
On 26 May 2011 14:52, Daniel Fischer <daniel.is.fischer at googlemail.com>wrote:
> On Thursday 26 May 2011 14:35:41, Neil Brown wrote:
> > foo is the function we want to apply, and eg shows how to apply it in
> > do-notation with an argument on each line. I couldn't manage to remove
> > the r$ at the beginning of each line, which rather ruins the whole
> > scheme :-( On the plus side, there's no brackets, it's only two extra
> > characters per line, and you can have whatever you like after the r$.
> Wouldn't that be also achievable with
> infixl 0 ?
> (?) :: (a -> b) -> a -> b
> f ? x = f x
> eg = foo
> ? 2 + 1
> ? 'c'
> ? "hello" ++ "goodbye"
> ? 3.0
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