[Haskell-cafe] ContT and ST stack
daniel.is.fischer at googlemail.com
Thu Mar 10 14:47:27 CET 2011
On Thursday 10 March 2011 14:18:24, Anakim Border wrote:
> Dear list,
> I have the following (simplified) piece of code:
> find :: Int -> [Int]
> find i = runST . (`runContT` return) $
> callCC $ \escape -> do
> return 
> which used to compile correctly under GHC 6.12.3.
> Now that I've switched to 7.0.2 it gets rejected with the following
> Couldn't match expected type `forall s. ST s c0'
> with actual type `m0 r0'
> Expected type: ContT r0 m0 a0 -> forall s. ST s c0
> Actual type: ContT r0 m0 a0 -> m0 r0
> In the second argument of `(.)', namely `(`runContT` return)'
> In the expression: runST . (`runContT` return)
> I'm a little bit lost at what exactly is the problem.
If memory serves correctly, it's impredicative polymorphism.
The type of (.), (b -> c) -> (a -> b) -> a -> c, can't handle
(x -> forall s. ST s [Int])
Previously there was an implementation of impredicative polymorphism which
allowed GHC to handle that construct, but that has been removed (because it
was unsatisfactory), so GHC 7 doesn't compile that anymore.
> Anyone can suggest a solution?
find i = runST ((`runContT` return) $
callCC $ \escape -> do
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