[Haskell-cafe] *GROUP HUG*

[Ertugrul Soeylemez]

Ivan Tarasov <ivan.tarasov at gmail.com> wrote:

> myFoldr :: (a -> b -> b) -> b -> [a] -> b
> myFoldr f z xs = foldl' (\s x v -> s (x `f` v)) id xs $ z

That's not foldr.  It's a function similar to foldr in Haskell and equal
to foldr in a different language, which lacks bottom.


Greets,
Ertugrul


-- 
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