[Haskell-cafe] *GROUP HUG*

[Don Stewart]

http://stackoverflow.com/questions/6172004/writing-foldl-using-foldr/6172270#6172270

Thank Graham Hutton and Richard Bird.

On Wed, Jun 1, 2011 at 7:12 PM, Tom Murphy <amindfv at gmail.com> wrote:
>>
>> How about this:
>>
>> myFoldr :: (a -> b -> b) -> b -> [a] -> b
>> myFoldr f z xs = foldl' (\s x v -> s (x `f` v)) id xs $ z
>>
>> Cheers,
>> Ivan
>>
>
>
> Great! Now I really can say "Come on! It's fun! I can write foldr with foldl!"
>
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