[Haskell-cafe] question regarding the $ apply operator

[Brandon Allbery]

On Tue, Jul 19, 2011 at 02:16, Ting Lei <tinlyx at hotmail.com> wrote:

> I have a naive question regarding the basic use of the $ operator, and I am
> confused why certain times it doesn't seem to work.
> e.g.
> The following works:
>
> applySkip i f ls = (take i) ls ++ f (drop i ls)
>
> But the following doesn't:
>
> applySkip i f ls = (take i) ls ++ f $ drop i ls
>

($) has lower precedence than almost every other operator, so your "doesn't
work" translates to

> applySkip i f ls = ((take i) ls ++ f) $ (drop i ls)

-- 
brandon s allbery                                      allbery.b at gmail.com
wandering unix systems administrator (available)     (412) 475-9364 vm/sms
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