[Haskell-cafe] Instantiation problem
patrick.browne at dit.ie
Sun Jan 30 11:27:08 CET 2011
On 29/01/2011 20:56, Henning Thielemann wrote:
> Is there a reason why you use an individual type for every unit?
> The existing implementations of typed physical units only encode the
> physical dimension in types and leave the unit factors to the value
> level. I found this to be the most natural way.
I am studying type classes using examples from the literature .
There is no particular intension to implement anything.
I am confused about the unit function in the code below.
My understanding is:
The signature of the unit function is defined in the MetricDescription
Any valid instantce of MetricDescription will respect the functional
The FD | description -> unit is exactly the signature of the unit function.
I do not understand the definitions of unit in the instances.
I do not know how the constant 1 can be equated with a *type*, Where did
1 come from?
I do not know how the constant 1 can be equated with *two distinct*
definitions of the function uint and still produce the following correct
Ok, modules loaded: A.
*A> unit (LengthInMetres 7)
*A> unit (LengthInCentimetres 7)
module A where
-- Each member of the Unit class has one operator convertFactorToBaseUnit
-- that takes a measurement unit (say metre) and returns a conversion
factor for that unit of measurement
class Unit unit where
convertFactorToBaseUnit :: unit -> Double
class (Unit unit) => MetricDescription description unit | description ->
unit :: description -> unit
valueInUnit :: description -> Double
valueInBaseUnit :: description -> Double
valueInBaseUnit d = (convertFactorToBaseUnit(unit d)) * (valueInUnit d)
data Dog = Dog deriving Show
data Metre = Metre deriving Show
data Centimetre = Centimetre deriving Show
-- An instance for metres, where the convert factor is 1.0
instance Unit Metre where
convertFactorToBaseUnit Metre = 1.0
-- An instance for centimetres, where the convert factor is 0.1
instance Unit Centimetre where
convertFactorToBaseUnit Centimetre = 0.1
data LengthInMetres = LengthInMetres Double deriving Show
data LengthInCentimetres = LengthInCentimetres Double deriving Show
instance MetricDescription LengthInMetres Metre where
valueInUnit (LengthInMetres d) = d
unit l = Metre
instance MetricDescription LengthInCentimetres Centimetre where
valueInUnit (LengthInCentimetres d) = d
unit l = Centimetre
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