[Haskell-cafe] How to get a file path to the program invoked?

[Thomas Schilling]

May I ask what the problem is you're trying to solve?

If you want to access datafiles in an installed program then Cabal can
help you with that.  See
http://www.haskell.org/cabal/users-guide/#accessing-data-files-from-package-code

If you want to do more complicated things, maybe take a look at how
GHC does it.  For example, on OS X (and other Unix-based systems) the
"ghc" command is actually a script:

$ cat `which ghc`
#!/bin/sh
exedir="/Library/Frameworks/GHC.framework/Versions/7.0.3-x86_64/usr/lib/ghc-7.0.3"
exeprog="ghc-stage2"
executablename="$exedir/$exeprog"
datadir="/Library/Frameworks/GHC.framework/Versions/7.0.3-x86_64/usr/share"
bindir="/Library/Frameworks/GHC.framework/Versions/7.0.3-x86_64/usr/bin"
topdir="/Library/Frameworks/GHC.framework/Versions/7.0.3-x86_64/usr/lib/ghc-7.0.3"
pgmgcc="/Developer/usr/bin/gcc"
executablename="$exedir/ghc"
exec "$executablename" -B"$topdir" -pgmc "$pgmgcc" -pgma "$pgmgcc"
-pgml "$pgmgcc" -pgmP "$pgmgcc -E -undef -traditional" ${1+"$@"}

/ Thomas

On 1 December 2011 16:12, dokondr <dokondr at gmail.com> wrote:
> Hi,
> When my program starts it needs to know a complete path to the directory
> from which it was invoked.
> In terms of standard shell (sh) I need the Haskell function that will do
> equivalent to:
>
> #!/bin/sh
> path=$(dirname $0)
>
> How to get this path in Haskell?
>
> getProgName :: IO String
> defined System.Environment only returns a file name of the program without
> its full path.
>
> Thanks!
>
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