[Haskell-cafe] Project Euler: request for comments

KC kc1956 at gmail.com
Mon Aug 29 00:56:52 CEST 2011


I just noticed that the 20x20 grid has some "00" entries; thus, time
could be saved by not touching any of the grid entries 3 cells away.
Same for the "01" entries.

The challenge, of course, is in finding these entries in the first place. :)


On Sun, Aug 28, 2011 at 1:58 PM, KC <kc1956 at gmail.com> wrote:
> Try something like the following:
>
> -- Project Euler 11
>
> -- In the 20×20 grid below, four numbers along a diagonal line have
> been marked in red.
>
> -- <snip>
>
> -- The product of these numbers is 26 × 63 × 78 × 14 = 1788696.
>
> -- What is the greatest product of four adjacent numbers in any
> direction (up, down, left, right, or diagonally) in the 20×20 grid?
>
>
> import Data.List
>
> -- Doing the one dimensional case.
> f011 :: [Int] -> Int
> f011 (t:u:v:xs) = f011helper t u v xs
>
> f011helper :: Int -> Int -> Int -> [Int] -> Int
> f011helper t u v (w:ws)
>   | ws == []  = t*u*v*w
>   | otherwise = yada nada mada
>
> -- What are yada nada mada?
>
> -- The 20x20 grid case will become:
> f0112D :: [[Int]] -> Int
> -- where [[Int]] is a list of lists of rows, columns, major diagonals,
> & minor diagonals.
>
>
>
> On Sun, Aug 28, 2011 at 5:10 AM, Oscar Picasso <oscarpicasso at gmail.com> wrote:
>> No. The answer I posted is not good.
>> It worked, by chance, on a couple of small examples I tried but it
>> could end up comparing sequence of 4 numbers that where not initially
>> adjacent.
>>
>> On Sun, Aug 28, 2011 at 12:32 AM, Oscar Picasso <oscarpicasso at gmail.com> wrote:
>>> Maybe this?
>>>
>>> f x@(a:b:c:d:[]) = x
>>> f (a:b:c:d:e:ys)  = if e >= a
>>>                   then f (b:c:d:e:ys)
>>>                   else f (a:b:c:d:ys)
>>>
>>> On Sat, Aug 27, 2011 at 8:26 PM, KC <kc1956 at gmail.com> wrote:
>>>> Think of the simplest version of the problem that isn't totally trivial.
>>>>
>>>> e.g. A one dimensional list of numbers.
>>>>
>>>> What would you do?
>>>>
>>>> Note: you only want to touch each element once.
>>>>
>>>> The 2 dimensional case could be handled by putting into lists: rows,
>>>> columns, major diagonals, and minor diagonals.
>>>>
>>>> This isn't the fastest way of doing the problem but it has the
>>>> advantage of avoiding "indexitis".
>>>>
>>>>
>
>
> --
> --
> Regards,
> KC
>



-- 
--
Regards,
KC



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