[Haskell-cafe] Do expression definition
Alexander Kotelnikov
sacha at myxomop.com
Mon Sep 13 03:21:59 EDT 2010
Hello.
http://www.haskell.org/onlinereport/exps.html#sect3.14 a obscure (to me) note which says
"As indicated by the translation of do, variables bound by let have fully polymorphic types while those defined by <- are lambda bound and are thus monomorphic."
What actually does it mean?
And, also, would it make any difference if
do {p <- e; stmts} = let ok p = do {stmts}
ok _ = fail "..."
in e >>= ok
is redefined as "e >>= (\p -> do {stmts})"?
Thanks, Alexander
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