[Haskell-cafe] About "Fun with type functions" example
Daniel Peebles
pumpkingod at gmail.com
Fri Nov 19 11:55:05 EST 2010
The "obvious" way to write the result would be (stealing some syntax made up
by ski on #haskell):
fromInt :: Int -> (exists n. (Nat n) *> n)
fromInt = ...
meaning, "at compile time we don't know the type of the result of fromInt,
because it depends on a runtime value, but we'll tell you it's _some_ type
(an existential) with a Nat instance".
Now, GHC haskell doesn't support existentials like that (you can make a
custom data type that wraps them) but you can invert your thinking a bit and
ask yourself _who_ can consume such an existential. The only kinds of
functions that can deal with an arbitrary type like that (with a Nat
instance) are those that are polymorphic in it. So instead of Int -> (exists
n. (Nat n) *> n), we flip the existential and make a continuation and say
Int -> (forall n. (Nat n) => n -> r) -> r, meaning we take the Int, and a
consumer of an arbitrary type-level natural, and return what the consumer
returns on our computed type-level natural. We're forced to return exactly
the value that the continuation returns because we know nothing at all about
the `r` type variable.
Hope this helps!
Dan
On Fri, Nov 19, 2010 at 9:09 AM, Arnaud Bailly <arnaud.oqube at gmail.com>wrote:
> Thanks a lot for the explanation. Summarizing: You can't calculate an
> exact type, but you don't care if the type of the continuation is
> properly set in order to "hide" the exact type of n? Am I right?
>
> Arnaud
>
> On Fri, Nov 19, 2010 at 9:24 AM, Miguel Mitrofanov
> <miguelimo38 at yandex.ru> wrote:
> > A continuation.
> >
> > You can't know, what type your "fromInt n" should be, but you're not
> going
> > to just leave it anyway, you're gonna do some calculations with it,
> > resulting in something of type r. So, your calculation is gonna be of
> type
> > (forall n. Nat n => n -> r). So, if you imagine for a moment that
> "fromInt"
> > is somehow implemented, what you're gonna do with it is something like
> >
> > calculate :: Int -> r
> > calculate i = let n = fromInt i in k n
> >
> > where k is of type (forall n. Nat n => n -> r). Now we capture this
> pattern
> > in a function:
> >
> > genericCalculate :: Int -> (forall n. Nat n => n -> r) -> r
> > genericCalculate i k = let n = fromInt i in k n
> >
> > Going back to reality, fromInt can't be implemented, but genericCalculate
> > probably can, since it doesn't involve calculating a type.
> >
> > 19.11.2010 10:25, Arnaud Bailly пишет:
> >>
> >> Just after hitting the button send, it appeared to me that fromInt was
> >> not obvious at all, and probably impossible.
> >> Not sure I understand your answer though: What would be the second
> >> parameter (forall n . (Nat n) => n -> r) -> r) ?
> >>
> >> Thanks
> >> Arnaud
> >>
> >> On Fri, Nov 19, 2010 at 1:07 AM, Daniel Peebles<pumpkingod at gmail.com>
> >> wrote:
> >>>
> >>> The best you can do with fromInt is something like Int -> (forall n.
> >>> (Nat n)
> >>> => n -> r) -> r, since the type isn't known at compile time.
> >>>
> >>> On Thu, Nov 18, 2010 at 2:52 PM, Arnaud Bailly<arnaud.oqube at gmail.com>
> >>> wrote:
> >>>>
> >>>> Thanks a lot, that works perfectly fine!
> >>>> Did not know this one...
> >>>> BTW, I would be interested in the fromInt too.
> >>>>
> >>>> Arnaud
> >>>>
> >>>> On Thu, Nov 18, 2010 at 8:22 PM, Erik Hesselink<hesselink at gmail.com>
> >>>> wrote:
> >>>>>
> >>>>> On Thu, Nov 18, 2010 at 20:17, Arnaud Bailly<arnaud.oqube at gmail.com>
> >>>>> wrote:
> >>>>>>
> >>>>>> Hello,
> >>>>>> I am trying to understand and use the Nat n type defined in the
> >>>>>> aforementioned article. Unfortunately, the given code does not
> compile
> >>>>>> properly:
> >>>>>
> >>>>> [snip]
> >>>>>
> >>>>>> instance (Nat n) => Nat (Succ n) where
> >>>>>> toInt _ = 1 + toInt (undefined :: n)
> >>>>>
> >>>>> [snip]
> >>>>>
> >>>>>> And here is the error:
> >>>>>>
> >>>>>> Naturals.hs:16:18:
> >>>>>> Ambiguous type variable `n' in the constraint:
> >>>>>> `Nat n' arising from a use of `toInt' at Naturals.hs:16:18-39
> >>>>>> Probable fix: add a type signature that fixes these type
> >>>>>> variable(s)
> >>>>>
> >>>>> You need to turn on the ScopedTypeVariables extension (using {-#
> >>>>> LANGUAGE ScopedTypeVariables #-} at the top of your file, or
> >>>>> -XScopedTypeVariables at the command line). Otherwise, the 'n' in the
> >>>>> class declaration and in the function definition are different, and
> >>>>> you want them to be the same 'n'.
> >>>>>
> >>>>> Erik
> >>>>>
> >>>> _______________________________________________
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> >>>
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