[Haskell-cafe] Re: How efficient is read?

[Brandon S. Allbery KF8NH]

On May 10, 2010, at 04:32 , Paul R wrote:
> Stephen> If you want to parse a stream, you don't want Parsec as
> Stephen> produces as it isn't an online parser - online meaning
>
> Thank you for this well detailed explanation. It was just me misusing
> the word "stream", I was actually meaning a simple bounded string.

That's not misuse, it's just confusing the usual parser terminology  
with the usual Haskell terminology.  (Hence also the earlier confusion  
about token streams in Parsec 3.)

-- 
brandon s. allbery [solaris,freebsd,perl,pugs,haskell] allbery at kf8nh.com
system administrator [openafs,heimdal,too many hats] allbery at ece.cmu.edu
electrical and computer engineering, carnegie mellon university    KF8NH


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