[Haskell-cafe] GHC vs GCC vs JHC

[Lennart Augustsson]

It's important to switch from mod to rem.  This can be done by a
simple abstract interpretation.
I'm nore sure if it's jhc or gcc that does this for jhc.

  -- Lennart

On Sat, Mar 27, 2010 at 10:30 PM, Rafael Cunha de Almeida
<almeidaraf at gmail.com> wrote:
> John Meacham wrote:
>> Here are jhc's timings for the same programs on my machine. gcc and ghc
>> both used -O3 and jhc had its full standard optimizations turned on.
>>
>> jhc:
>> ./hs.out  5.12s user 0.07s system 96% cpu 5.380 total
>>
>> gcc:
>> ./a.out  5.58s user 0.00s system 97% cpu 5.710 total
>>
>> ghc:
>> ./try  31.11s user 0.00s system 96% cpu 32.200 total
>>
>>
>> As you can see, jhc shines at this example, actually beating gcc -O3. It
>> isn't too surprising, this is exactly the sort of haskell code that jhc
>> excels at.
>
> What's the property of that code which makes jhc excels in it? What
> makes ghc perform so poorly in comparison?
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