[Haskell-cafe] Re: really difficult for a beginner like me...
daniel.is.fischer at web.de
Wed Mar 24 09:44:24 EDT 2010
Von: saaj [
Gesendet: 24.03.2010 13:13:29
An: haskell-cafe at haskell.org
Betreff: [Haskell-cafe] Re: really difficult for a beginner like me...
>saaJamal [ hotmail.com> writes:
>U happen to find a way for your problem? I tried a lot for more than a week
>now, but cant do it.
>I tried many tutorials but wasnt of any good.
>as per the above case study, I need to do is:
>1) Allow words to be hyphenated and treat a hyphenated
>word as a single word. However, for those words which are split over two
>lines, treat a split word as a single word without the hyphen.
>for this i tried:
> fixupHyphens :: [ (Int, Word) ] -> [ (Int, Word ) ]
> fixupHyphens ( (line1, word1):(line2:word2):xs )
> | if (word1, line2) /= line1 = ( line1,word2 ) : fixupHyphens xs
> | otherwise = (line1, word1):(line2:word2): fixupHyphens xs
> fixupHyphens xs = xs
It's probably easier to treat the hyphens before pairing the words with the line-numbers.
If you needn't care about words containing a hyphen (like line-numbers above), a simple preprocessor
fixHyphens :: String -> String
fixHyphens ('-':'\n':more) = (move rest of the word before the newline and remove hyphen)
fixHyphens (c:cs) = c: fixHyphens cs
fixHyphens "" = ""
should do the trick.
>and for including hiphens i added this to the code:
> splitWords :: Line -> [Word] -- a)
> splitWords  = 
> splitWords line
> = takeWhile isLetter line : -- first word in line
> (splitWords . -- split other words
> dropWhile (not.isLetter) . -- delete separators
> dropWhile isLetter) line -- other words
> isLetter ch
> = (('a'<=ch) && (ch<='z'))
> || (('A'<=ch) && (ch<='Z'))
> || ('-' = ch)
>2)Treat a capitalised word (one or more capitals) as being different from the
>word in all lower case (but they should still be sorted alphabetically)unless
>it is at the start of a sentence with only the initial letter capitalised.
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