[Haskell-cafe] Removing alternate items from a list

[Mike Dillon]

OK, here's mine:

    f as = [ x | (True,x) <- zip (cycle [True, False]) as ]

-md

begin R J quotation:
> 
> What's the cleanest definition for a function f :: [a] -> [a] that takes a list and returns the same list, with alternate items removed?  e.g., f [0, 1, 2, 3, 4, 5] = [1,3,5]?
>  		 	   		  
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