[Haskell-cafe] Haddock question

[S. Doaitse Swierstra]

Unfortunately I get for input:

-- | We can now run the parser @`pa`@ on input \"a\", which succeeds: 
-- @ 
--   Result: \"a\"
--   Second line
-- @

the output

We can now run the parser pa on input "a", which succeeds: Result: "a" Second line

Doaitse






On 21 jul 2010, at 16:17, Daniel Fischer wrote:

> On Wednesday 21 July 2010 16:09:37, S. Doaitse Swierstra wrote:
>> I am trying to document my parser library. In order to do so I should
>> like to include some example output in my haddock documentation. I fail
>> to see however how to get a block of output into the haddock part.
>> 
>> E.g.
>> 
>> -- | We can now run the parser @`pa`@ on input \"a\", which succeeds:
>> -- @ Result: \"a\"
>> -- @
> 
> -- | We can now ...
> --
> -- @
> --   Result: \"a\"
> -- @
> --
> --  In further news, ...
> 
>> 
>> does not put the Result ... on a separate line, and if I have several
>> lines of output they are concatenated.
>> 
>> How to proceed,
>> 
>> Doaitse
>> 
> 
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